Assuming a B-spline smoother, we have that \(\hat{\boldsymbol{y}} = \boldsymbol{H}(\boldsymbol{H}^T\boldsymbol{H})^{-1}\boldsymbol{H}^T\boldsymbol{y}\), where \(\boldsymbol{H}\) is a B-spline basis matrix.
Hints for problem 8.4
Published Oct. 9, 2025 6:23 PM
- Last modified Oct. 9, 2025 6:26 PM